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24p^2-6p-12=6
We move all terms to the left:
24p^2-6p-12-(6)=0
We add all the numbers together, and all the variables
24p^2-6p-18=0
a = 24; b = -6; c = -18;
Δ = b2-4ac
Δ = -62-4·24·(-18)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-42}{2*24}=\frac{-36}{48} =-3/4 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+42}{2*24}=\frac{48}{48} =1 $
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